Answer by Quentin for Uglifying JavaScript - Further optimisation
In short, because there is too much potential for the code to break.Assuming you mean var _g=_gaq.push;, then two possible causes of breakage spring to mind:You've changed the value of this inside...
View ArticleUglifying JavaScript - Further optimisation
This might seem like a stupid question but is there some reason why Uglifiers don't uglify references to external functions using a pointer?An example:A file I'm working on has multiple calls to...
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